How do you graph #y= 0.84( 2.01) ^ { x }#?

1 Answer
Aug 5, 2017

Well, we know it should be similar to the parent exponential function, #f(x) = e^x#:

Graph of #f(x) = e^x#:

graph{e^x [-10.67, 9.33, -2.48, 7.52]}

And the graph of #f(x) = (0.84)(2.01)^x# is

graph{0.84*2.20^x [-10.67, 9.33, -2.48, 7.52]}

We notice that the second graph is vertically shrunk because the graph appears wider. This comes from the fact that the function is multiplied by a value of #0.84# to expand it from the normal multiplier of #1#...

It is also slightly horizontally shrunk because the value of #2.01# is slightly less than the value of #e# (#2.7182818#).