How do you graph #y=(1/4)^x# and #y=(1/4)^x-1# and how do the graphs compare?

1 Answer
Feb 18, 2018

See explanation.

Explanation:

To graph the equation #y=(1/4)^x# you can substitute some values. For example you can easily calculate:

#f(0)=1#, #f(1)=1/4#, #f(-1)=4#.

To graph the equation you can also use the propertes of exponential function.

If #0 < a < 1# then #f(x)=a^x# is decreasing in its whole domain, it goes to #+oo# as #x# goes to #-oo#, and goes to #0# as #x# goes to #+oo#.

Using these information you get:

graph{(1/4)^x [-25.65, 25.67, -12.82, 12.85]}

The second graph #y=(1/4)^x -1# can be obtained from the first by translating it one unit down (i.e. by a vector #vec(v)=[0;-1]#):

graph{(1/4)^x-1 [-25.65, 25.67, -12.82, 12.85]}