# How do you graph y < |2x + 3|?

When $\left(2 x + 3\right) < 0$
$y < \left\mid 2 x + 3 \right\mid \text{implies " y " is below the line } y = - 2 x - 3$
For ease of drawing the graph, note that $y = - 2 x - 3$ has intercepts at $\left(0 , - 3\right) \text{ and } \left(- \frac{3}{2} , 0\right)$
When $\left(2 x + 3\right) \ge 0$
$y < \left\mid 2 x + 3 \right\mid \text{implies " y " is below the line } y = 2 x + 3$
Again, for ease of drawing the graph, note that $y = 2 x + 3$ has intercepts at $\left(0 , + 3\right) \text{ and } \left(- \frac{3}{2} , 0\right)$