How do you graph #y = 2x - 3#?

1 Answer
Dec 1, 2015

Plot the point with the y-intercept #(0,-3)#. Use the slope #2/1# to move up 2 and over 1 to find a second point at #(1,-1)#. Draw a straight line through the points.

Explanation:

#y=2x-3# is in slope intercept form for a linear equation, #y=mx+b#, where #m# is the slope and #b# is the y-intercept.

The y-intercept is the point at which #x=0# and #y=-3#, which is point #(0,-3)# You can plot this point on your graph.

The slope is can be described as #"rise"/"run"#, and can be written as #2/1#. Start at #(0,3)#. The next point would be found by moving up 2 and over 1. This would give point #(1,-1)#. You can keep doing this as long as you want, but for a straight line, you really only need two points.

Draw a straight line between the two points.

graph{y=2x-3 [-14.24, 14.23, -7.12, 7.12]}