How do you graph #y=2x#?

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Answer 1 · 2018-03-04T22:14:29

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = 2 xx 0#

#y = 0# or #(0, 0)#

Second Point: For #x = 1#

#y = 2 xx 1#

#y = 2# or #(1, 2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+y^2-0.025)((x-1)^2+(y-2)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 2x)(x^2+y^2-0.025)((x-1)^2+(y-2)^2-0.025)=0 [-10, 10, -5, 5]}