How do you graph #y=-2x+7#?

1 Answer
Jun 2, 2018

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 2#

#y = (-2 * 2) + 7#

#y = -4 + 7#

#y = 3# or #(2, 3)#

Second Point: For #x = 4#

#y = (-2 * 4) + 7#

#y = -8 + 7#

#y = -1# or #(4, -1)#

We can next plot the two points on the coordinate plane:

graph{((x-2)^2+(y-3)^2-0.035)((x-4)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + 2x - 7)((x-2)^2+(y-3)^2-0.035)((x-4)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}