How do you graph #y<-3/4x+2#?

1 Answer
Jul 22, 2017

Refer to the explanation below.

Explanation:

Graph:

#y<-3/4x+2#

Determine two points on the line. The x-intercept and the y-intercept are useful. The x-intercept is the point where #y=0#. The y-intercept is the point where #x=0#.

X-Intercept

#x=8/3, y=0#

Point: #(8/3,0)#

Y-Intercept

#x=0, y=2#

Point: #(0,2)#

Plot the points on the graph and draw a dashed line through them to indicate that the line is not part of the graph. Shade in the area beneath the line to indicate the #<# inequality.

graph{y<-3/4x+2 [-10, 10, -5, 5]}