How do you graph #y = 3x + 8#?

1 Answer
Apr 11, 2016

Answer:

See the explanation

Explanation:

#color(blue)("Determine "y_("intercept"))#

At y intercept #x=0# so by substitution we have

#y_("intercept")=3(0)+8 #

#color(blue)(y_("intercept")->(x,y)-> (0,8))#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Determine "x_("intercept")#

x intercept is at #y=0# so by substitution we have

#0=3(x_("intercept")) +8#

#color(blue)(=>x_("intercept") ->(x,y)->(8/3 ,0)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Mark these two points an draw a line through them. Extend this line to edges of the axis scales.