How do you graph #y+4=1/3(x+6)#?

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Answer 1 · 2018-06-29T14:43:17

See a solution process below:

First, solve the equation for #y# to make it easier to work with:

#y + 4 = (1/3 xx x) + (1/3 xx 6)#

#y + 4 = 1/3x + 2#

#y + 4 - color(red)(4) = 1/3x + 2 - color(red)(4)#

#y + 0 = 1/3x - 2#

#y = 1/3x - 2#

Next, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (1/3 xx 0) - 2#

#y = 0 - 2#

#y = -2# or #(0, -2)#

Second Point: For #x = 6#

#y = (1/3 xx 6) - 2#

#y = 2 - 2#

#y = 0# or #(6, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.04)((x-6)^2+y^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - (1/3)x + 2)(x^2+(y+2)^2-0.04)((x-6)^2+y^2-0.04)=0 [-10, 10, -5, 5]}