# How do you graph y+4=1/3(x+6)?

Jun 29, 2018

See a solution process below:

#### Explanation:

First, solve the equation for $y$ to make it easier to work with:

$y + 4 = \left(\frac{1}{3} \times x\right) + \left(\frac{1}{3} \times 6\right)$

$y + 4 = \frac{1}{3} x + 2$

$y + 4 - \textcolor{red}{4} = \frac{1}{3} x + 2 - \textcolor{red}{4}$

$y + 0 = \frac{1}{3} x - 2$

$y = \frac{1}{3} x - 2$

Next, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$y = \left(\frac{1}{3} \times 0\right) - 2$

$y = 0 - 2$

$y = - 2$ or $\left(0 , - 2\right)$

Second Point: For $x = 6$

$y = \left(\frac{1}{3} \times 6\right) - 2$

$y = 2 - 2$

$y = 0$ or $\left(6 , 0\right)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.04)((x-6)^2+y^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - (1/3)x + 2)(x^2+(y+2)^2-0.04)((x-6)^2+y^2-0.04)=0 [-10, 10, -5, 5]}