# How do you graph y-4x=0 by plotting points?

Mar 12, 2017

see below

#### Explanation:

By adding $4 x$ on both sides of the equation, we obtain $y = 4 x$. We can plot point in the $x y$-plane by choosing values of $x$.

For example, let's choose $x = - 2 , - 1 , 0 , 1 ,$and $2$ for simplicity.
When:
$x = - 2$, $y = 4 \left(- 2\right) = - 8$, so the point is $\left(- 2 , - 8\right)$.
$x = - 1$, $y = 4 \left(- 1\right) = - 4$, so the point is $\left(- 1 , - 4\right)$.
$x = 0$, $y = 4 \left(0\right) = 0$, so the point is $\left(0 , 0\right)$.
$x = 1$, $y = 4 \left(1\right) = 4$, so the point is $\left(1 , 4\right)$.
$x = 2$, $y = 4 \left(2\right) = 8$, so the point is $\left(2 , 8\right)$.

The graph should look something like this after you plot the points and connect the points from above.
graph{y=4x [-5, 5, -10, 10]}