How do you graph #y-4x=0# by plotting points?

1 Answer
Mar 12, 2017

see below

Explanation:

By adding #4x# on both sides of the equation, we obtain #y=4x#. We can plot point in the #xy#-plane by choosing values of #x#.

For example, let's choose #x=-2, -1, 0, 1, #and #2# for simplicity.
When:
#x=-2#, #y=4(-2)=-8#, so the point is #(-2,-8)#.
#x=-1#, #y=4(-1)=-4#, so the point is #(-1,-4)#.
#x=0#, #y=4(0)=0#, so the point is #(0,0)#.
#x=1#, #y=4(1)=4#, so the point is #(1,4)#.
#x=2#, #y=4(2)=8#, so the point is #(2,8)#.

The graph should look something like this after you plot the points and connect the points from above.
graph{y=4x [-5, 5, -10, 10]}