How do you graph #y=-x+3# and #y=-4x-6#?

1 Answer
Jul 31, 2018

See a solution process below:

Explanation:

To graph these two linear equations for each equation we need to:

  • Solve each equation for two points.
  • Plot the two points
  • Draw a straight line through the two points to graph the line for the equation.

Equation 1:

  • First Point: For #x = 0#

#y = -0 + 3#

#y = 3# or #(0, 3)#

  • Second Point: For #x = 3#

#y = -3 + 3#

#y = 0# or #(3, 0)#

We can next plot the two points on the coordinate plane and draw a line through the two points.:

graph{(y+x-3)(x^2+(y-3)^2-0.04)((x-3)^2+y^2-0.045)=0 [-20, 20, -10, 10]}

Equation 2:

  • First Point: For #x = 0#

#y = (-4 xx 0) - 6#

#y = 0 - 6#

#y = -6# or #(0, -6)#

  • Second Point: For #x = -2#

#y = (-4 xx -2) - 6#

#y = 8 - 6#

#y = 2# or #(-2, 2)#

We can next plot the two points on the coordinate plane and draw a line through the two points.:

graph{(y+4x+6)(y+x-3)(x^2+(y+6)^2-0.075)((x+2)^2+(y-2)^2-0.075)=0 [-20, 20, -10, 10]}