Question

How do you graph `y=x^3/(x^4-1)`?

Answer 1

See explanation

Explanation:

You will have to build a table of values for intermediate values

You have 2 asymptotes. One at `x=+1` and the other at `x=-1`

The denominator has excluded values for `x^4=1` as `1-1=0`

as `(x^3)/(x^4-1) -> 1/0" or " (-1)/0` which are undefined
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`lim_(x->-oo) =-1/(+oo) =color(white)(.)^(-) 0`

`lim_(x->+oo) = color(white)(..)1/(+oo)=color(white)(.)^(+) 0`