How do you graph #y<(x+4)^2-1#?

1 Answer
Douglas K.
Nov 8, 2016

Please see the explanation

Explanation:

Draw a parabola that opens upward as a dashed line to indicate that it is not included.
The vertex is at #(-4, -1)#
The roots are at #(-3, 0)# and #(-5, 0)#
It is symmetrical about the vertical line #x = -4#

Shade in everything outside the parabola and leave all of the points inside the parabola unshaded. Here is a picture:

enter image source here

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