Question

How do you identify `cos^2x/(1-sinx)`?

Answer 1

The answer is `=1+sinx`

Explanation:

We need

`a^2-b^2=(a+b)(a-b)`

We use

`cos^2x+sin^2x=1`

`cos^2x=1-sin^2x=(1+sinx)(1-sinx)`

Therefore,

`cos^2x/(1-sinx)=((1+sinx)cancel(1-sinx))/cancel(1-sinx)`

`=1+sinx`