# How do you use implicit differentiation to find #(d^2y)/dx^2# of #x^3+y^3=1# ?

##### 1 Answer

By implicitly differentiating twice, we can find

First, let us find

by differentiating with respect to

by subtracting

by dividing by

Now, let us find

by differentiating with respect to

by plugging in

by multiplying the numerator and the denominator by

by plugging in