How do you find the derivative of $y = f (x) - g (x)$ $y = f(x) - g(x)$ ?

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Answer 1 · 2014-10-10T23:42:44

The derivative for $y = f (x) - g (x)$ $y=f(x)-g(x)$ works the same way as the derivative of $y = f (x) + g (x)$ $y=f(x)+g(x)$ .

$y=f(x)-g(x) => dy/dx=f'(x)-g'(x)$

The quick proof is:
$y=f(x)-g(x)=f(x)+(-1)g(x)$
Using the sum rule and the constant rule:
$dy/dx=f'(x)+(-1)g'(x)=f'(x)-g'(x)$ .

How do you find the derivative of y = f(x) - g(x)y=f(x)−g(x)y = f(x) - g(x)?