Question

How do you integrate `1/x^2`?

Answer 1

`int1/(x^2)dx=-1/x+C`

Explanation:

This function can be written as `x^-2`.

To integrate such function we can use the general formula:

`int x^alpha=x^(alpha+1)/(alpha+1)` for any rational `alpha`

Using this formula we get:

`int1/(x^2)dx=intx^(-2)dx=x^-1/(-1)+C=-1/x+C`