Question

How do you integrate `(2x)/(x²-1)`?

Answer 1

`int (2x)/(x^2-1) d x=l n(x^2-1)+C`

Explanation:

`int (2x)/(x^2-1) d x=?`

`x^2-1=u`

`2x d x=d u`

`int (2x)/(x^2-1) d x=int (d u)/u=l n u +C`

`int (2x)/(x^2-1) d x=l n(x^2-1)+C`