How do you integrate #\int 12x ^ { 5} d x#?
1 Answer
Dec 1, 2016
Explanation:
We will use the rules:
#intaf(x)dx=aintf(x)dx# #intx^ndx=x^(n+1)/(n+1)+C#
Thus:
#int12x^5dx=12intx^5dx=12(x^6/6)+C=2x^6+C#