Question

How do you integrate `\int _ { 2} ^ { - 3} ( 3+ x ^ { 2} ) ^ { 2} d x`?

Answer 1

`-170`

Explanation:

Expanding
`(3+x^2)^2=9+6x^2+x^4`
we have
`int_2^(-3)(9+6x^2+x^4)dx`
so we have
`[9x+2x^3+x^5/5]_2^(-3)=-170`