Question

How do you integrate `\int \tan x + \sec x d x`?

Answer 1

The answer is `=-ln(|cosx|)+ln(|tanx+secx|)+C`

Explanation:

We need

`inttanxdx=-ln(cosx)+C`

and

`intsecxdx=ln(tanx+secx)+C`

Therefore,

`int(tanx+secx)dx=-ln(|cosx|)+ln(|tanx+secx|)+C`