How do you integrate #(ln x)^2 dx#?
1 Answer
May 22, 2016
Use integration by parts twice to find that
Explanation:
We will proceed using integration by parts :
Integration by parts (i):
Let
Then
Applying the integration by parts formula
#=xln^2(x)-2intln(x)dx" (1)"#
Integration by parts (ii):
Focusing on the remaining integral, let
Then
Applying the formula:
#=xln(x) - intdx#
#=xln(x) - x + C#
Substituting this back into
#=xln^2(x)-2xln(x)+2x+C#