How do you integrate (x+2)/(x+3)?

$\frac{x + 2}{x + 3} = 1 - \frac{1}{x + 3}$
$\textcolor{b l u e}{\int \frac{x + 2}{x + 3} \mathrm{dx}}$
$= \textcolor{b l u e}{x - \ln | x + 3 | + C}$