How do you integrate $xe^(x^2) dx$ ?

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Answer 1 · 2016-08-14T20:20:09

This can be done by substitution. See explanation.

$intxe^(x^2)dx=|(t=x^2),(dt=2xdx),(dt/2=xdx)|=int(e^t/2)dt=1/2int(e^tdt)$

$=1/2e^t+C=1/2e^(x^2)+C$

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