How do you know how many roots are in a polynomial?

1 Answer
Sep 9, 2017

See explanation...

Explanation:

Fundamental Theorem of Algebra

The Fundamental Theorem of Algebra (FTOA) tells us that any non-zero polynomial in one variable with complex (possibly real) coefficients has a complex zero.

A straightforward corollary, often stated as part of the FTOA is that a polynomial in a single variable of degree n > 0n>0 with complex (possibly real) coefficients has exactly nn complex (possibly real) zeros, counting multiplicity.

To see that the corollary follows, note that if f(x)f(x) is a polynomial of degree n > 0n>0 and f(a) = 0f(a)=0, then (x-a)(xa) is a factor of f(x)f(x) and f(x)/(x-a)f(x)xa is a polynomial of degree n-1n1. So repeatedly applying the FTOA, we find that f(x)f(x) has exactly nn complex zeros counting multiplicity.

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Discriminants

If you want to know how many real roots a polynomial with real coefficients has, then you might like to look at the discriminant - especially if the polynomial is a quadratic or cubic. Ths discriminant gives less information for polynomials of higher degree.

The discriminant of a quadratic ax^2+bx+cax2+bx+c is given by the formula:

Delta = b^2-4ac

Then:

Delta > 0 indicates that the quadratic has two distinct real zeros.

Delta = 0 indicates that the quadratic has one real zero of multiplicity two (i.e. a repeated zero).

Delta < 0 indicates that the quadratic has no real zeros. It has a complex conjugate pair of non-real zeros.

The discriminant of a cubic ax^3+bx^2+cx+d is given by the formula:

Delta = b^2c^2-4ac^3-4b^3d-27a^2d^2+18abcd

Then:

Delta > 0 indicates that the cubic has three distinct real zeros.

Delta = 0 indicates that the cubic has either one real zero of multiplicity 3 or one real zero of multiplicity 2 and another real zero.

Delta < 0 indicates that the cubic has one real zero and a complex conjugate pair of non-real zeros.