How do you know if #f(x)=1/(x^3+1)# is an even or odd function?

1 Answer
Nov 27, 2015

It isn't even nor odd.

Explanation:

To see if a function is even or odd, you must evaluate #f(-x)#, and there are three possibilites:

  1. If #f(-x)=f(x)#, the function is even;
  2. If #f(-x)=-f(x)#, the function is odd;
  3. Otherwise, it's none of the two.

In this case,

#f(-x)=1/(-x^3+1)#, which is not equal to the original function, and it's neither its opposite (which would be #1/(-x^3-1)#). So, the function is not even nor odd