How do you know if F(x) = (2x) / absx is an even or odd function?

1 Answer
Dec 8, 2015

F is odd.

Explanation:

Method 1

Consider F(-x),

if F(-x)=F(x) for all x in the domain of F, then F is even

if F(-x)=-F(x) for all x in the domain of F, then F is odd

if F(-x) is not always F(x) and not always -F(x), then F is neither even nor odd.

F(x)=(2x)/absx

F(-x) = (2(-x))/abs(-x) = (-2x)/absx " " " " (Note: abs(-x)=absx).

So, F(-x)=-F(x) for all x in the domain of F, and, therefore, F is odd.

Method 2

Simplify F(x)=(2x)/absx using the definition of absolute value.

absx = {(" "x," if",x >= 0),(-x," if",x<0) :}

Note that F is not defined at x=0, so we get:

F(x) = {((2x)/x," if",x > 0),((2x)/(-x)," if",x<0) :}.

Simplifying, gets us:

F(x) = {(" "2," if",x > 0),(-2," if",x<0) :}

At this point it is clear that F(-x) = -F(x) for all x in the domain of F. (Because for every x != 0, we have -x is on the oppposite side of 0.)