How do you know if #f(x)= sqrt ( x^2 -3)# is an even or odd function?

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Answer 1 · 2018-07-02T12:16:17

#f(x)# is an "even" function.

A function is "even" when # f(-x)= f(x)# for all #x#

The function is a symmetry about #y# axis

#f(x) = sqrt (x^2-3)#

#f(-x) = sqrt ((-x)^2-3) = sqrt (x^2-3)#

# f(-x)= f(x)# , the graph also shows its symmetry about

#y# axis , so it is an "even" function.

graph{(x^2-3)^0.5 [-20, 20, -10, 10]} [Ans]