How do you know if G(x) = sqrtx is an even or odd function?

1 Answer
Nov 23, 2015

It is neither odd nor even.

Explanation:

Get G(-x).

If G(-x)=G(x), then it is even.

If G(-x)=-G(x), then it is odd.

If neither is true, then it is neither odd nor even.

Solution

First, we restrict the domain of G(x) to [0,+oo).

" "G(-x)=sqrt(-x)

However, -x will always be negative or 0. So when you get the square root of -x, the answer will only either be 0 or imaginary.

Conclusion It is neither odd nor even.