How do you multiply #(3xy^5)(6x^4y^2)#?
1 Answer
Oct 26, 2014
Multiplication is fairly simple: all you need to do is multiply the like terms first and multiply your products.

First, let's take the constants (the numbers). The two numbers are
#3# and#6# . Be careful and always remember to take the negative sign. Multiplying them, we have:
#(3)*(6)=18# 
Now, let's take the second pair of like terms: with the variable
#x# .
Multiplying#x# with#x^4# , we have:
#(x)*(x^4)=x^5#
Remember, that when the bases are equal, powers can be added up! So,#(x)*(x^4)=(x^1)*(x^4)=x^(1+4)=x^5# 
Now, multiplying the third pair: with the variable
#y# .
Multiplying#y^5# with#y^2# , we have:
#(y^5)*(y^2)=y^(5+2)=y^7#
Thus, by multiplying all three products, we get: