How do you multiply #(10r + 4) ( 10r - 4)#?

1 Answer
smendyka
Jun 2, 2017

See a solution process below:

Explanation:

This is a special for of multiplying terms. Use this rule:

#(a + b)(a - b) = a^2 - b^2#

Substituting #10r# for #a# and #4# for #b# gives:

#(10r + 4)(10r - 4) => (10r)^2 - 4^2 => 100r^2 - 16#

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