How do you multiply (18x-36)/(4x-8)*2/(9x+18) and state the excluded values?

1 Answer
Nov 1, 2016

= 1/(x+2)

x !=2 and x != -2

Explanation:

(18x-36)/(4x-8)*2/(9x+18)" "larr factorise first

=(18(x-2) xx2)/(4(x-2)xx9(x+2))

=(cancel18^cancel2cancel{(x-2)} xx cancel2)/(cancel4cancel{(x-2)}xxcancel9(x+2))" "larr cancel like factors

= 1/(x+2)

Remember that the denominator may not be zero,
The excluded values are therefore the values which
would give us 0.