How do you multiply #((2, 1, 2), (0, -1, 3))# and #((4, 7), (-2, -1), (0, 3))#?

1 Answer
Mar 4, 2017

See below.

Explanation:

I really do wish Socratic had a convenient (or any) drawing tool, as it would make this so much easier.

In summary, here you've got a #2 times color(red)(3)# matrix and a #color(red)(3) times 2# matrix , so you're gonna get a #2 times 2# matrix.

You can do this via an elemental summation formula:

#(A B)_(ij) = sum_k A_(i, color(red)(k)) B_(color(red)(k) , j) #

And so to start, it's 24 + 1 (-2) + 2*(0).....that's just row 1, column 1.

From there, you process the patterns.