How do you multiply #((2, 1, 2), (0, -1, 3))# and #((4, 7), (-2, -1), (0, 3))#?
1 Answer
Mar 4, 2017
See below.
Explanation:
I really do wish Socratic had a convenient (or any) drawing tool, as it would make this so much easier.
In summary, here you've got a
You can do this via an elemental summation formula:
And so to start, it's 24 + 1 (-2) + 2*(0).....that's just row 1, column 1.
From there, you process the patterns.