Question

How do you multiply `((2, 8), (6, 3))` with `((3, 0), (2, -1))`?

Answer 1

`((a_11, a_12),(a_21, a_22))`

Explanation:

The product is `A`.

`a_11 = 2 * 3 + 8 * 2`
`a_12 = 2 * 0 + 8(-1)`
`a_21 = 6 * 3 + 3 * 2`
`a_22 = 6 * 0 + 3(-1)`

`A = ((22, -8),(24, -3))`