How do you multiply #2sqrt2* sqrt12#?

2 Answers
Jim G.
Aug 10, 2017

#4sqrt6#

Explanation:

#"using the "color(blue)"laws of radicals"#

#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#

#rArr2sqrt2xxsqrt12#

#=2xxsqrt(2xx12)#

#=2xxsqrt24#

#=2xxsqrt(4xx6)#

#=2xxsqrt4xxsqrt6#

#=2xx2xxsqrt6#

#=4xxsqrt6=4sqrt6#

jim p. · EZ as pi
Aug 10, 2017

Move the leftmost #2# under the first root sign. (you have to square it). Then multiply the two quantities under root signs.

Explanation:

#2 * (sqrt(2)) = sqrt (2 * 4) = sqrt (8).# You can check on a calculator.

Then, #sqrt(8) * sqrt(12) = sqrt(12 * 8) = sqrt(96)#

# = 9.7979# and some change.

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