How do you multiply $- 2 x (x - 5 x)$ $-2x ( x - 5x )$ ?

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Answer 1 · 2017-07-17T14:42:32

See a solution process below:

Multiply each term within the parenthesis by the term outside the parenthesis:

$- 2 x (x - 5 x) \Rightarrow$ $color(red)(-2x)(x - 5x) =>$

$(- 2 x \times x) - (- 2 x \times 5 x) \Rightarrow$ $(color(red)(-2x) xx x) - (color(red)(-2x) xx 5x) =>$

$- 2 x^{2} - (- 10 x^{2}) \Rightarrow$ $-2x^2 - (-10x^2) =>$

$- 2 x^{2} + 10 x^{2} \Rightarrow$ $-2x^2 + 10x^2 =>$

$(- 2 + 10) x^{2} \Rightarrow$ $(-2 + 10)x^2 =>$

$8 x^{2}$ $8x^2$

Another process would be to add the terms within the parenthesis first and then multiply the result:

$- 2 x (x - 5 x) \Rightarrow$ $-2x(x - 5x) =>$

$- 2 x (1 x - 5 x) \Rightarrow$ $-2x(1x - 5x) =>$

$- 2 x ([1 - 5] x) \Rightarrow$ $-2x([1 - 5]x) =>$

$- 2 x (- 4 x) \Rightarrow$ $-2x(-4x) =>$

$8 x^{2}$ $8x^2$

How do you multiply −2x(x−5x)-2x ( x - 5x )?