If you didn't already know, we can use the #"F.O.I.L"# method.
#"F.O.I.L"# stands for:
#color(red)"F"#: First, as in you multiply the first two terms in each #()#
#color(blue)"O"#: Outer (multiply the outer terms)
#color(green)"I"#: Inner (multiply the inner terms)
#color(orange)"L"#: Last (multiply the last terms
#(color(red)(2y)+11)(color(red)(2y)-11) : color(red)(4y^2)#
#(color(blue)(2y)+11)(2ycolor(blue)(-11)) : color(blue)(-22y)#
#(2y+color(green)(11))(color(green)(2y)-11) : color(green)(22y)#
#(2y+color(orange)(11))(2ycolor(orange)(-11)) : color(orange)(-121)#
Gathering this information, we can rewrite the expression and combine like terms:
#4y^2color(red)(-22y+22y)-121#
#4y^2cancel(color(red)(-22y+22y))-121#
The middle terms cancel and so we are left with this as our final answer:
#4y^2-121#
