How do you multiply #(2y - 5) ( 4y + 7x + 4)#?

1 Answer
smendyka
Jul 15, 2017

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2y) - color(red)(5))(color(blue)(4y) + color(blue)(7x) + color(blue)(4))# becomes:

#(color(red)(2y) xx color(blue)(4y)) + (color(red)(2y) xx color(blue)(7x)) + (color(red)(2y) xx color(blue)(4)) - (color(red)(5) xx color(blue)(4y)) - (color(red)(5) xx color(blue)(7x)) - (color(red)(5) xx color(blue)(4))#

#8y^2 + 14xy + 8y - 20y - 35x - 20#

We can now combine like terms:

#8y^2 + 14xy + (8 - 20)y - 35x - 20#

#8y^2 + 14xy + (-12)y - 35x - 20#

#8y^2 + 14xy - 12y - 35x - 20#

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