How do you multiply #(3r + 6) ( r - 1)#?

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Answer 1 · 2018-01-15T03:49:36

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3r) + color(red)(6))(color(blue)(r) - color(blue)(1))# becomes:

#(color(red)(3r) xx color(blue)(r)) - (color(red)(3r) xx color(blue)(1)) + (color(red)(6) xx color(blue)(r)) - (color(red)(6) xx color(blue)(1))#

#3r^2 - 3r + 6r - 6#

We can now combine like terms:

#3r^2 + (-3 + 6)r - 6#

#3r^2 + 3r - 6#