How do you multiply #(3sqrtx^5)(2sqrtx^3)#?

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Answer 1 · 2018-03-03T01:29:22

The answer is #6x^4#.

You can rewrite #sqrtx^5# as #x^(5/2)#, and #sqrtx^3# as #x^(3/2)#:

#color(white)=(3sqrtx^5)(2sqrtx^3)#

#=(3x^(5/2))(2x^(3/2))#

#=3*2*x^(5/2)*x^(3/2)#

#=6*x^(5/2)*x^(3/2)#

#=6*x^(5/2+3/2)#

#=6*x^(8/2)#

#=6*x^4#

The answer is #6x^4#.