How do you multiply #(3x + 2) ( 4x - 3) #?

1 Answer
Jim G.
Dec 20, 2016

#12x^2-x-6#

Explanation:

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.

#rArr(color(red)(3x+2))(4x-3)#

#=color(red)(3x)(4x-3)color(red)(+2)(4x-3)#

distribute the brackets.

#=12x^2-9x+8x-6#

collect like terms.

#=12x^2-x-6#

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