How do you multiply #(3x+2)(x^2+2x+4)#?

1 Answer
Jim G.
Aug 1, 2017

#3x^3+8x^2+16x+8#

Explanation:

#"each term in the second factor is multiplied by each term"#
#"in the first factor"#

#(color(red)(3x+2))(x^2+2x+4)#

#=color(red)(3x)(x^2+2x+4)color(red)(+2)(x^2+2x+4)#

#"distributing the brackets gives"#

#(color(red)(3x)xx x^2)+(color(red)(3x)xx2x)+(color(red)(3x)xx4)+(color(red)(2)xx x^2)+(color(red)(2)xx2x)+(color(red)(2)xx4)#

#=3x^3+6x^2+12x+2x^2+4x+8#

#"collecting like terms gives"#

#3x^3+8x^2+16x+8#

Related questions
Impact of this question
416 views around the world
You can reuse this answer
Creative Commons License