How do you multiply #(4- 5i ) ( 7+ 8i )#?

1 Answer

#68-3i#

Explanation:

We use FOIL:

  • #color(red)(F)# - First terms - #(color(red)(a)+b)(color(red)(c)+d)#

#4xx7=28#

  • #color(brown)(O)# - Outside terms - #(color(brown)(a)+b)(c+color(brown)d)#

#4xx8i=32i#

  • #color(blue)(I)# - Inside terms - #(a+color(blue)b)(color(blue)(c)+d)#

#-5ixx7=-35i#

  • #color(green)(L)# - Last terms - #(a+color(green)b)(c+color(green)d)#

#-5ixx8i=-40i^2=-40xx-1=40#

And now add them up:

#28+32i-35i+40=68-3i#