How do you multiply #(4- 5i ) ( 7+ 8i )#?
1 Answer
Jun 25, 2017
Explanation:
We use FOIL:
#color(red)(F)# - First terms -#(color(red)(a)+b)(color(red)(c)+d)#
#4xx7=28#
#color(brown)(O)# - Outside terms -#(color(brown)(a)+b)(c+color(brown)d)#
#4xx8i=32i#
#color(blue)(I)# - Inside terms -#(a+color(blue)b)(color(blue)(c)+d)#
#-5ixx7=-35i#
#color(green)(L)# - Last terms -#(a+color(green)b)(c+color(green)d)#
#-5ixx8i=-40i^2=-40xx-1=40#
And now add them up: