You can first multiply #4.7xx7.6=35.72# and then deal with the powers of ten remembering that #a^m*a^m=a^(m+n)#; #10^(-8)*10^3=10^(-8+3)=10^(-5)#
So you get: #35.72xx10^(-5)# rearranged to have: #3.572xx10^(-4)# by moving the decimal point to the left and changing, as a consequence, the exponent of #10# of 1 unit.