How do you multiply #(4+ \sqrt { 3} ) ( 3- 2\sqrt { 3} )#?

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Answer 1 · 2017-07-31T08:01:43

#3sqrt3 -18#

Multiply the brackets out using the #F O I L # approach, or just bt multiplying #4# and the second bracket and #sqrt3# by the second bracket.

#(4+sqrt3)(3-2sqrt3)#

#=4(3-2sqrt3)+sqrt3(3-2sqrt3)#

#= 12-8sqrt3^2 +3sqrt3 -2sqrt3^2" "larr (sqrt3^2=3)#

#=12-24+3sqrt3-6#

#=3sqrt3 -18#

You could factorise, but I don't think it helps at all.

#=3(sqrt3-6)#