How do you multiply (4c^2)/(4c) *( -3p^2)/(-3p^3)?

$\frac{c}{p}$
We have $\frac{4 {c}^{2}}{4 c} = c$ and $\frac{- 3 {p}^{2}}{- 3 {p}^{3}} = \frac{1}{p}$ so we get $\frac{c}{p}$