How do you multiply #-4h ^ { 4} j ^ { - 4} k ^ { 3} \cdot - k#?

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Answer 1 · 2016-10-19T19:23:19

# (4h^4k^4)/(j^4)#

Assumption: The question is intended that the dot means multiply:

#-4h^4j^(-4)k^3xx(-k)#

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Consider the example #2^(-4)# this is the same as #1/(2^4)#

So using the above answer #j^(-4)->1/(j^4)#

Thus we have: #-(4h^4k^3)/(j^4) xx(-k)#

When multiplying and the signs are the same the answer is positive.

When multiplying and the signs are not the same the answer is negative.

We have a minus times a minus so the answer is positive

#+ (4h^4k^4)/(j^4)#

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Foot note

On Socratic if you want multiply use xx
So #->" hash 2x xx 3 hash "->2x xx 3#