How do you multiply #(4j - 1) ( 3j - 4)#?

1 Answer
EZ as pi
Dec 15, 2016

#= 12j^2 -19j +4#

Explanation:

Using the distributive law, each term in the first bracket must be multiplied by each term in the second bracket.

This is sometimes called the FOIL method: (Firsts, Outers, Inners, Lasts)

#(color(red)(4j - color(blue)(1)))(3j -4)#

=#color(red)(12j^2 -16j color(blue)(-3j +4)" "larr# collect like terms

#= 12j^2 -19j +4#

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