# How do you multiply (4sqrt3-5sqrt2)(2sqrt3+3sqrt2)?

$= {\overbrace{\left[4 \sqrt{3} \cdot 2 \sqrt{3}\right]}}^{\text{First") + overbrace([4sqrt3*3sqrt2])^("Outer") + overbrace([-5sqrt2*2sqrt3])^("Inner") + overbrace([-5sqrt2*3sqrt2])^("Last}}$
$= 8 \cdot 3 + 12 \sqrt{6} - 10 \sqrt{6} - 15 \cdot 2$
$= - 6 + 2 \sqrt{6}$