How do you multiply #(4x - 12) ( x + 3) #?

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Answer 1 · 2017-07-21T02:48:25

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(4x) - color(red)(12))(color(blue)(x) + color(blue)(3))# becomes:

#(color(red)(4x) xx color(blue)(x)) + (color(red)(4x) xx color(blue)(3)) - (color(red)(12) xx color(blue)(x)) - (color(red)(12) xx color(blue)(3))#

#4x^2 + 12x - 12x - 36#

We can now combine like terms:

#4x^2 + (12 - 12)x - 36#

#4x^2 + 0x - 36#

#4x^2 - 36#